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4x^2+60x-240=0
a = 4; b = 60; c = -240;
Δ = b2-4ac
Δ = 602-4·4·(-240)
Δ = 7440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7440}=\sqrt{16*465}=\sqrt{16}*\sqrt{465}=4\sqrt{465}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{465}}{2*4}=\frac{-60-4\sqrt{465}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{465}}{2*4}=\frac{-60+4\sqrt{465}}{8} $
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